<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[PIR sensor to cut backlight power]]></title><description><![CDATA[<p dir="auto">Hi, need some help from you guys :)</p>
<p dir="auto">I’m planing to use a PIR sensor to cut power to the backlight board of my LCD. I dont want to shut down my monitor or the signal to it due to the anoying “no signal” and “Input” screens.</p>
<p dir="auto">Dont think I need any code for this as I should be able to use the pir without any action from the Pi, I just draw power from it.</p>
<p dir="auto">As my LCD driver board has an add-on board just for the backlight it should be easy. As I can gather I have two options.</p>
<ol>
<li>Use a relay  to cut the 12v connection between lcd driverboard and inverter.</li>
<li>Disregard the relay and connect the PIR directly to inverter as it has a ON/OFF wire connection set as HIGH when ON</li>
</ol>
<p dir="auto">As my skills in schematics and power distrubution is rather limited I could use your inputs on my two options and please have a look on my fancy pictures, the only connection that is in place is the one connecting LCD driver board and inverter. Have I missed anyting? should that wiring work?</p>
<ol>
<li></li>
</ol>
<p dir="auto"><img src="/uploads/files/1471280357543-untitled-presentation.jpg" alt="0_1471280355179_Untitled presentation.jpg" class=" img-fluid img-markdown" /></p>
<ol start="2">
<li></li>
</ol>
<p dir="auto"><img src="/uploads/files/1471280389245-untitled-presentation-1.jpg" alt="0_1471280387057_Untitled presentation (1).jpg" class=" img-fluid img-markdown" /></p>
]]></description><link>https://forum.magicmirror.builders/topic/503/pir-sensor-to-cut-backlight-power</link><generator>RSS for Node</generator><lastBuildDate>Wed, 22 Apr 2026 05:48:34 GMT</lastBuildDate><atom:link href="https://forum.magicmirror.builders/topic/503.rss" rel="self" type="application/rss+xml"/><pubDate>Mon, 15 Aug 2016 17:00:58 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to PIR sensor to cut backlight power on Tue, 16 Aug 2016 11:34:17 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/tomaszmuda" aria-label="Profile: TomasZmuda">@<bdi>TomasZmuda</bdi></a></p>
<p dir="auto">Great! Thank you so much!</p>
<p dir="auto">option 1 only cuts 12v to the inverter, not the main board so should have the same effect as option 2 but if I can drop the relay it’s one less thing to power so with your help I will go for option 2 for sure :)</p>
<p dir="auto">thanks again!</p>
]]></description><link>https://forum.magicmirror.builders/post/3734</link><guid isPermaLink="true">https://forum.magicmirror.builders/post/3734</guid><dc:creator><![CDATA[MrH]]></dc:creator><pubDate>Tue, 16 Aug 2016 11:34:17 GMT</pubDate></item><item><title><![CDATA[Reply to PIR sensor to cut backlight power on Tue, 16 Aug 2016 11:25:35 GMT]]></title><description><![CDATA[<p dir="auto">I’m using the second option, because LCD’s boot up time is about 8 sec.</p>
<p dir="auto">But you have to hook up ground, as i updated your schema. Otherwise the PIR will have zero ground.</p>
<p dir="auto"><img src="/uploads/files/1471346554595-untitled_ldvs.jpg" alt="0_1471346555046_untitled_ldvs.jpg" class=" img-fluid img-markdown" /></p>
]]></description><link>https://forum.magicmirror.builders/post/3733</link><guid isPermaLink="true">https://forum.magicmirror.builders/post/3733</guid><dc:creator><![CDATA[TomasZmuda]]></dc:creator><pubDate>Tue, 16 Aug 2016 11:25:35 GMT</pubDate></item><item><title><![CDATA[Reply to PIR sensor to cut backlight power on Tue, 16 Aug 2016 11:16:29 GMT]]></title><description><![CDATA[<p dir="auto">Indeed, but then I get that annoying OSD window telling me what input is selected :) And by keeping power to the main board but cut power to the light inverter gives me a drop from 38w to 6-7w. For me, thats a win if it means I get rid of that OSD input window ;)</p>
]]></description><link>https://forum.magicmirror.builders/post/3731</link><guid isPermaLink="true">https://forum.magicmirror.builders/post/3731</guid><dc:creator><![CDATA[MrH]]></dc:creator><pubDate>Tue, 16 Aug 2016 11:16:29 GMT</pubDate></item><item><title><![CDATA[Reply to PIR sensor to cut backlight power on Tue, 16 Aug 2016 11:02:53 GMT]]></title><description><![CDATA[<p dir="auto">Or, you could simply remove power from the board, so 0w consumation whien you don’t need it. Add the relay to the power cable of the board (my board needs 1 sec to turn all on this way)</p>
]]></description><link>https://forum.magicmirror.builders/post/3730</link><guid isPermaLink="true">https://forum.magicmirror.builders/post/3730</guid><dc:creator><![CDATA[L_i_v_e]]></dc:creator><pubDate>Tue, 16 Aug 2016 11:02:53 GMT</pubDate></item></channel></rss>