PIR sensor to cut backlight power
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Hi, need some help from you guys
I’m planing to use a PIR sensor to cut power to the backlight board of my LCD. I dont want to shut down my monitor or the signal to it due to the anoying “no signal” and “Input” screens.
Dont think I need any code for this as I should be able to use the pir without any action from the Pi, I just draw power from it.
As my LCD driver board has an add-on board just for the backlight it should be easy. As I can gather I have two options.
- Use a relay to cut the 12v connection between lcd driverboard and inverter.
- Disregard the relay and connect the PIR directly to inverter as it has a ON/OFF wire connection set as HIGH when ON
As my skills in schematics and power distrubution is rather limited I could use your inputs on my two options and please have a look on my fancy pictures, the only connection that is in place is the one connecting LCD driver board and inverter. Have I missed anyting? should that wiring work?
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Or, you could simply remove power from the board, so 0w consumation whien you don’t need it. Add the relay to the power cable of the board (my board needs 1 sec to turn all on this way)
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Indeed, but then I get that annoying OSD window telling me what input is selected
And by keeping power to the main board but cut power to the light inverter gives me a drop from 38w to 6-7w. For me, thats a win if it means I get rid of that OSD input window 
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I’m using the second option, because LCD’s boot up time is about 8 sec.
But you have to hook up ground, as i updated your schema. Otherwise the PIR will have zero ground.
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Great! Thank you so much!
option 1 only cuts 12v to the inverter, not the main board so should have the same effect as option 2 but if I can drop the relay it’s one less thing to power so with your help I will go for option 2 for sure
thanks again!
